James 6

James and Lisa shared some sweets. James took 2/7 of the sweets, and Lisa took the rest. If James took 18 fewer sweets than Lisa, how many sweets did they have altogether at first?

Correct answer:

n =  42

Step-by-step explanation:

J=2/7 n L=nJ = n  2/7 n = 5/7 n J = L18  72 n=75 n18  2/7 n=5/7 n18  3n=126  n=3126=42  n=42   Verifying Solution:  J=72 n=72 42=72 42=784=12 L=nJ=4212=30 d=LJ=3012=18

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