What is the surface area of 50 cm iceberg (in the shape of a cuboid) that can carry a man with luggage with a total weight of 120 kg?

Correct result:

S =  3 m2


h=50 cmm=50/100 m=0.5 m m=120 kg  ρ1=1000 kg/m3 ρ2=920 kg/m3  ρ=ρ1ρ2=1000920=80 kg/m3  m=ρV  V=m/ρ=120/80=32=1.5 m3 V=Sh  S=V/h=1.5/0.5=3 m2h=50 \ cm \rightarrow m=50 / 100 \ m=0.5 \ m \ \\ m=120 \ \text{kg} \ \\ \ \\ ρ_{1}=1000 \ \text{kg/m}^3 \ \\ ρ_{2}=920 \ \text{kg/m}^3 \ \\ \ \\ ρ=ρ_{1}-ρ_{2}=1000-920=80 \ \text{kg/m}^3 \ \\ \ \\ m=ρ V \ \\ \ \\ V=m/ρ=120/80=\dfrac{ 3 }{ 2 }=1.5 \ \text{m}^3 \ \\ V=Sh \ \\ \ \\ S=V/h=1.5/0.5=3 \ \text{m}^2

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