Shot

Shot with a mass 39 g flying at 427 m/s penetrates into the wood to a depth 21 cm.

What is the average force of resistance of wood?

Correct answer:

F =  16930.55 N

Step-by-step explanation:

m=39 g kg=39:1000  kg=0.039 kg v=427 m/s h=21 cm m=21:100  m=0.21 m  F = ma a = v/t s = 21 at2 = 21 vt t=v2 h=4272 0.21=305030.001 s a=2 hv2=2 0.214272434116.6667 m/s2  F=m a=0.039 434116.6667=16930.55 N



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