Truncated cone

Calculate the height of the rotating truncated cone with volume V = 1471 cm3 and a base radii r1 = 6.1 cm and r2 = 7.9 cm.

Final Answer:

h =  9.5 cm

Step-by-step explanation:

r1=6.1 cm r2=7.9 cm V=1471 cm3  V = 31 π h (r12+r1 r2+r22) = 31 S   h  S=π (r12+r1 r2+r22)=3.1416 (6.12+6.1 7.9+7.92)464.3588 cm2  h=S3 V=464.35883 1471=9.5 cm



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Showing 5 comments:
Math student
can u explain why you do (r2 + rxR + R2) in the first step

6 years ago  3 Likes
Dr Math
Fine math problem! Go ahead!

Kukoslav
but to prove formula, you need to know how to solve integral

Kukoslav
need to solve a cubic equation, as obtained above, to find rises in heights... integral





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