Truncated cone

Calculate the height of the rotating truncated cone with volume V = 1115 cm3 and a base radii r1 = 7.9 cm and r2 = 9.7 cm.

Correct result:

h =  4.57 cm

Solution:

r1=7.9 cm r2=9.7 cm V=1115 cm3  V=13πh(r12+r1 r2+r22)  h=3⋅ Vπ⋅ (r12+r1⋅ r2+r22)=3⋅ 11153.1416⋅ (7.92+7.9⋅ 9.7+9.72)=4.57 cm

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Showing 5 comments:
#
Dr Math

#
Math student
can u explain why you do (r2 + rxR + R2) in the first step

1 year ago  3 Likes
#
Dr Math
Fine math problem! Go ahead!

#
Kukoslav
but to prove formula, you need to know how to solve integral

#
Kukoslav
need to solve a cubic equation, as obtained above, to find rises in heights... integral

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