Alcohol 2

Two types of alcohol one 63% and second 75% give 20 liters of 69% alcohol. How many liters of each type are in the mixture?

Result

A =  10
B =  10

Solution:


A+B = 20
A*(63/100)+B*(75/100)=20*(69/100)

A+B = 20
63A+75B = 1380

A = 10
B = 10

Calculated by our linear equations calculator.








Leave us a comment of example and its solution (i.e. if it is still somewhat unclear...):

Showing 2 comments:
#1
Nestor
Your solution did not use the "given" in the problem i.e., instead of 70%< you used 69%.

#2
Dr Math
Fixed this typo problem, thank you!

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