Air

Room is 35.6 m long, 19.6 dm wide and 591 cm high. How many people can simultaneously be in this room if for hygiene reasons is calculated 5000 dm3 of air per person?

Result

n =  82

Solution:

a=35.6 m b=19.6 dm=19.6/10 m=1.96 m c=591 cm=591/100 m=5.91 m  V1=a b c=35.6 1.96 5.91412.3762 m3 V2=5000 dm3=5000/1000 m3=5 m3  n=V1/V2=412.3762/5=82a=35.6 \ \text{m} \ \\ b=19.6 \ dm=19.6 / 10 \ m=1.96 \ m \ \\ c=591 \ cm=591 / 100 \ m=5.91 \ m \ \\ \ \\ V_{ 1 }=a \cdot \ b \cdot \ c=35.6 \cdot \ 1.96 \cdot \ 5.91 \doteq 412.3762 \ \text{m}^3 \ \\ V_{ 2 }=5000 \ dm^3=5000 / 1000 \ m^3=5 \ m^3 \ \\ \ \\ n=\lfloor V_{ 1 }/V_{ 2 } \rfloor=\lfloor 412.3762/5 \rfloor=82



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