Circle and square

An ABCD square with a side length of 100 mm is given. Calculate the radius of the circle that passes through the vertices B, C and the center of the side AD.

Correct result:

r =  62.5 mm

Solution:

a=100 mm r2=x2+(a/2)2 r+x=a  r2=(ra)2+(a/2)2  r2=r22 ra+a2+(a/2)2  2 r a=a2+(a/2)2  r=a2+(a/2)22 a  r=58 a=58 100=1252=1252 mm=62.5 mm



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