Quadrilateral pyramid

The height of a regular quadrilateral pyramid is 6.5 cm, and the angle between the base and the side wall is 42°. Calculate the surface area and volume of the body—round calculations to 1 decimal place.

Correct answer:

S =  489 cm2
V =  451.7 cm3

Step-by-step explanation:

h=6.5 cm α=42   tan α = h : (a/2) a=2 h/tanα=2 h/tan42° =2 6.5/tan42° =2 6.5/0.900404=14.43796 cm  S1=a2=14.4382208.4548 cm2  h2=h2+(a/2)2=6.52+(14.438/2)29.7141 cm  S2=a h2/2=14.438 9.7141/270.1259 cm2  S=S1+4 S2=208.4548+4 70.1259=489 cm2
V=31 S1 h=31 208.4548 6.5=451.7 cm3

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