Quadrilateral pyramid

In a regular quadrilateral pyramid, the height is 6.5 cm and the angle between the base and the side wall is 42°. Calculate the surface area and volume of the body. Round calculations to 1 decimal place.

Correct answer:

S =  273 cm2
V =  225.8 cm3

Step-by-step explanation:

h=6.5 cm A=42   tanA=h:(u/2) u=2 h/tanA=2 h/tan42° =2 6.5/tan42° =2 6.5/0.900404=14.43796 cm  a=u/2=14.438/210.2092 cm  S1=a2=10.20922104.2274 cm2  h2=h2+(a/2)2=6.52+(10.2092/2)28.2648 cm  S2=a h2/2=10.2092 8.2648/242.1884 cm2  S=S1+4 S2=104.2274+4 42.1884=273 cm2
V=31 S1 h=31 104.2274 6.5=225.8 cm3

Did you find an error or inaccuracy? Feel free to write us. Thank you!

Showing 1 comment:
Thank u i was trying to find the answer to that in class(my teacher let us look it up and i said it so i got it right.

1 year ago  1 Like

Tips to related online calculators
Pythagorean theorem is the base for the right triangle calculator.
Tip: Our volume units converter will help you with the conversion of volume units.
See also our trigonometric triangle calculator.

We encourage you to watch this tutorial video on this math problem: video1   video2

Related math problems and questions: