Regular quadrilateral pyramid

What is the volume of a regular quadrilateral pyramid if its surface is 576 cm2 and the base edge is 16 cm?

Correct answer:

V =  512 cm3

Step-by-step explanation:

S=576 cm2 a=16 cm  S1=a2=162=256 cm2  S4=(SS1)/4=(576256)/4=80 cm2  S4 = a h2 /2  h2=2 S4/a=2 80/16=10 cm  h=h22(a/2)2=102(16/2)2=6 cm  V=31 S1 h=31 256 6=512 cm3

Did you find an error or inaccuracy? Feel free to write us. Thank you!

Tips for related online calculators
See also our right triangle calculator.
Tip: Our volume units converter will help you convert volume units.

We encourage you to watch this tutorial video on this math problem: video1   video2

Related math problems and questions: