Regular quadrilateral pyramid

What is the volume of a regular quadrilateral pyramid if its surface is 576 cm2 and the base edge is 16 cm?

Correct result:

V =  1375.9587 cm3

Solution:

S=576 cm2 a=16 cm  S1=a2=162=256 cm2  S4=(SS4)/4=(576144)/4=144 cm2  S4=ah2/2  h2=2 S4/a=2 144/16=18 cm  h=h22(a/2)2=182(16/2)2=2 65 cm16.1245 cm  V=13 S1 h=13 256 16.1245=1375.9587 cm3



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