# Right Δ

A right triangle has the length of one leg 11 cm and length of the hypotenuse 61 cm. Calculate the height of the triangle.

Result

vc =  10.8 cm

#### Solution:

$a = 11 \ cm \ \\ c = 61 \ cm \ \\ b = \sqrt{ c^2-a^2 } = 60 \ cm \ \\ \ \\ S = S \ \\ \dfrac{1}{2} c v_c = \dfrac{1}{2} a b \ \\ c v_c = a b \ \\ c v_c = a v_c = \dfrac{a}{c} b = \dfrac{ 11}{ 61} \cdot 60 = 10.8 \ \text{ cm }$

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