The pond

We can see the pond at an angle 65°37'. Its end points are 155 m and 177 m away from the observer. What is the width of the pond?

Result

c =  180.836 m

Solution:

a=155 m b=177 m  A=65+3760=39376065.6167   c=a2+b22 a b cosA=a2+b22 a b cos65.6166666667 =1552+17722 155 177 cos65.6166666667 =a2+b22 a b 0.41284=180.83555=180.836 ma=155 \ \text{m} \ \\ b=177 \ \text{m} \ \\ \ \\ A=65 + \dfrac{ 37 }{ 60 }=\dfrac{ 3937 }{ 60 } \doteq 65.6167 \ ^\circ \ \\ \ \\ c=\sqrt{ a^2 + b^2 -2 \cdot \ a \cdot \ b \cdot \ \cos A ^\circ }=\sqrt{ a^2 + b^2 -2 \cdot \ a \cdot \ b \cdot \ \cos 65.6166666667^\circ \ }=\sqrt{ 155^2 + 177^2 -2 \cdot \ 155 \cdot \ 177 \cdot \ \cos 65.6166666667^\circ \ }=\sqrt{ a^2 + b^2 -2 \cdot \ a \cdot \ b \cdot \ 0.41284 }=180.83555=180.836 \ \text{m}

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Pythagorean theorem is the base for the right triangle calculator.
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See also our trigonometric triangle calculator.

 
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