Barrel with water

The water barrel has a weight of 52 kg. When we pour a quarter of the water, the weight of the barrel is reduced to 40 kg. Determine the weight of the empty barrel.

Correct result:

m =  4 kg

Solution:

$$\begin{gathered} m+v=52 \\ m+(v-v\mathrm{/}4)=40 \\ m+v=52 \\ 4m+3v=160 \\ m=4=4\text{ kg } \\ v=48 \end{gathered}$$

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