Diamond and diagonals

A diamond has diagonals f = 8 cm and g = 6 cm long. How long is this diamond perimeter? (Calculate it!)

Correct result:

o =  20 cm

Solution:

$f=8 \ \text{cm} \ \\ g=6 \ \text{cm} \ \\ \ \\ a=\sqrt{ (f/2)^2+(g/2)^2 }=\sqrt{ (8/2)^2+(6/2)^2 }=5 \ \text{cm} \ \\ o=4 \cdot \ a=4 \cdot \ 5=20 \ \text{cm}$

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