Metal tube

Calculate the metal tube mass 8dm long with the outer radius 5cm and the inner radius 4.5cm and 1cm3 of this metal is 9.5g.

Result

m =  11.341 kg

Solution:

r1=4.5 cm r2=5 cm l=8 dm=8⋅ 10 cm=80 cm  S=π⋅ r22−π⋅ r12=3.1416⋅ 52−3.1416⋅ 4.52≐14.9226 cm2   V=S⋅ l=14.9226⋅ 80≐1193.8052 cm3  r=9.5 g/cm3 m1=r⋅ V=9.5⋅ 1193.8052≐11341.1495 g  m=m1→kg=m1/1000 kg=11.34115 kg=11.341 kgr_{1}=4.5 \ \text{cm} \ \\ r_{2}=5 \ \text{cm} \ \\ l=8 \ dm=8 \cdot \ 10 \ cm=80 \ cm \ \\ \ \\ S=\pi \cdot \ r_{2}^2 - \pi \cdot \ r_{1}^2=3.1416 \cdot \ 5^2 - 3.1416 \cdot \ 4.5^2 \doteq 14.9226 \ \text{cm}^2 \ \\ \ \\ \ \\ V=S \cdot \ l=14.9226 \cdot \ 80 \doteq 1193.8052 \ \text{cm}^3 \ \\ \ \\ r=9.5 \ \text{g/cm}^3 \ \\ m_{1}=r \cdot \ V=9.5 \cdot \ 1193.8052 \doteq 11341.1495 \ \text{g} \ \\ \ \\ m=m_{1} \rightarrow kg=m_{1} / 1000 \ kg=11.34115 \ kg=11.341 \ \text{kg}

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