# Center of the cube

Center of the cube has distance 33 cm from each vertex.

Calculate the volume V and surface area S of the cube.

Result

V =  55328.6 cm3
S =  8712 cm2

#### Solution:

$u = 2 \cdot 33 = 66 \ cm \ \\ u = \sqrt{3} a \ \\ a = \dfrac{u}{\sqrt{3}} = \dfrac{ 66 }{\sqrt{3}} = 38.105 \ cm \ \\ V = a^3 = 38.105^3 = 55328.6 \ \text{cm}^3$
$S = 6a^2 = 6\cdot 38.105^2 = 8712 \ \text{cm}^2$

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