Angle of the body diagonals

Using vector dot product calculate the angle of the body diagonals of the cube.

Correct answer:

A =  70.5288 °

Step-by-step explanation:

D1=(1,1,1) D2=(1,1,1)  d1=D1 d1=12+12+12=31.7321  d2=D2 d2=12+12+(1)2=31.7321  D1 D2=d1 d2cosA  c=cosA=D1 D2d1d2  c=1 1+1 1+1 (1)d1 d2=1 1+1 1+1 (1)1.7321 1.7321=130.3333  A0=arccos(c)=arccos(0.3333)1.231 rad  A=A0  °=A0 180π   °=1.231 180π   °=70.529  °=70.5288°=70°3144"



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