Angle of the body diagonals

Using the vector dot product calculate the angle of the body diagonals of the cube.

Final Answer:

A =  70.5288 °

Step-by-step explanation:

D1 = (1,1,1) D2 = (1,1,1)  d1 = D1 d1=12+12+12=31.7321  d2 = D2 d2=12+12+(1)2=31.7321  D1   D2 = d1 d2  cos A  c = cos A =  d1  d2D1 D2  c=d1 d21 1+1 1+1 (1)=1.7321 1.73211 1+1 1+1 (1)=310.3333  A0=arccosc=arccos0.33331.231 rad  A=A0  °=A0 π180   °=1.231 π180   °=70.529  °=70.5288=70°3144"



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Tips for related online calculators
Our vector sum calculator can add two vectors given by their magnitudes and by included angle.
See also our right triangle calculator.
See also our trigonometric triangle calculator.

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geometryarithmeticsolid geometryplanimetricsgoniometry and trigonometryUnits of physical quantitiesGrade of the word problem

 
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