# TV tower

Calculate the height of the television tower if an observer standing 430 m from the base of the tower sees the peak at an altitude angle of 23°?

Correct result:

y =  182.524 m

#### Solution:

$x=430 \ \text{m} \ \\ A=23 \ ^\circ \ \\ \ \\ \tan A=\dfrac{ y }{ x } \ \\ \ \\ y=x \cdot \ \tan A ^\circ =x \cdot \ \tan 23^\circ \ =430 \cdot \ \tan 23^\circ \ =430 \cdot \ 0.424475=182.524 \ \text{m}$ Our examples were largely sent or created by pupils and students themselves. Therefore, we would be pleased if you could send us any errors you found, spelling mistakes, or rephasing the example. Thank you!

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