# Triangle in a square

In a square ABCD with side a = 6 cm, point E is the center of side AB and point F is the center of side BC. Calculate the size of all angles of the triangle DEF and the lengths of its sides.

Correct result:

d =  2.1213 cm
e =  6.7082 cm
f =  6.7082 cm
E =  71.5651 °
F =  71.5651 °
D =  36.8699 °

#### Solution:

$F=E=71.5651=71.565{1}^{\circ }=7{1}^{\circ }3{3}^{\mathrm{\prime }}54\mathrm{"}$
$D=180-F-E=180-71.5651-71.5651=36.869{9}^{\circ }=3{6}^{\circ }5{2}^{\mathrm{\prime }}12\mathrm{"}$

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