# Coils of transformer

The primary coil of the transformer has 400 turns, a current of 1.5 A passes through it and is connected to a voltage of 220 V. For the secondary coil, find the voltage, current, and a number of turns if the transformation ratio k = 0.1.

Correct result:

U2 =  22 V
I2 =  0.15 A
N2 =  40

#### Solution:

$N_{2}=k \cdot \ N_{1}=0.1 \cdot \ 400=40$

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Math student
i think the value of I2=0.15A

Math student
k=i2/i1  which is wrong

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