Motion

If you go at speed 3.7 km/h, you come to the station 42 minutes after leaving the train. If you go by bike to the station at speed 27 km/h, you come to the station 56 minutes before its departure.
How far is the train station?

Correct result:

s =  7.003 km

Solution:

v1=3.7 km/h v2=27 km/h t1=(x+42)/60 t2=(x56)/60 s=v1 t1=v2 t2 v1(x+42)=v2(x56) x=(v1 42+v2 56)/(v2v1)=(3.7 42+27 56)/(273.7)71.5622 min t1=(x+42)/60=(71.5622+42)/60=4412331.8927 h t2=(x56)/60=(71.562256)/600.2594 h  s=s1=s2 s1=v1 t1=3.7 1.89277.003 km s=v2 t2=27 0.2594=7.003 km



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