Equation of circle 2

Find the equation of a circle that touches the axis of y at a distance of 4 from the origin and cuts off an intercept of length 6 on the axis x.

Result

f : (Correct answer is: ) OK

Step-by-step explanation:

A = (0,4) B = (x0​+6/2,0) C = (x0​−6/2,0)  (x−x0​)2 + (y−y0​)2 = r2  (0−x0​)2 + (4−y0​)2 = r2 (x0​+3−x0​)2 + (0−y0​)2 = r2 (x0​−3−x0​)2 + (0−y0​)2 = r2  x02​ + (4−y0​)2 = r2 9 + y02​ = r2 9 + y02​ = r2  r=5 x0​=5 y0​=4  f=(x−5)2+(y−4)=52

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