Equation of circle 2

Find the equation of a circle that touches the axis of y at a distance of 4 from the origin and cuts off an intercept of length 6 on the axis x.


f : (Correct answer is: ) OK

Step-by-step explanation:

A = (0,4) B = (x0+6/2,0) C = (x06/2,0)  (xx0)2 + (yy0)2 = r2  (0x0)2 + (4y0)2 = r2 (x0+3x0)2 + (0y0)2 = r2 (x03x0)2 + (0y0)2 = r2  x02 + (4y0)2 = r2 9 + y02 = r2 9 + y02 = r2  r=5 x0=5 y0=4  f=(x5)2+(y4)=52

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