Equation of circle 2

Find the equation of a circle which touches the axis of y at a distance 4 from the origin and cuts off an intercept of length 6 on the axis x.

Result

f = (Correct answer is: ) OK

Solution:

A=(0,4) B=(x0+6/2,0) C=(x0−6/2,0)  (x−x0)2+(y−y0)2=r2  (0−x0)2+(4−y0)2=r2 (x0+3−x0)2+(0−y0)2=r2 (x0−3−x0)2+(0−y0)2=r2  x02+(4−y0)2=r2 9+y02=r2 9+y02=r2  r=5 x0=5 y0=4  f=(x−5)2+(y−4)=52

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