Right triangle eq2

Find the lengths of the sides and the angles in the right triangle. Given area S = 210 and perimeter o = 70.

Correct answer:

a =  21
b =  20
c =  29
A =  46.3972 °
B =  43.6028 °
C =  90 °

Step-by-step explanation:


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b=2 S/a=2 210/21=20 b=a2=20
c=a2+b2=212+202=29
A=180°πarcsin(a/c)=180°πarcsin(21/29)=46.3972°=46°2350"
B=180°πarcsin(b/c)=180°πarcsin(20/29)=43.6028°=43°3610"
C=90=90°



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