Right triangle eq2

Find the lengths of the sides and the angles in the right triangle. Given area S = 210 and perimeter o = 70.

Correct answer:

a =  21
b =  20
c =  29
A =  46.3972 °
B =  43.6028 °
C =  90 °

Step-by-step explanation:


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b=2 S/a=2 210/21=20 b=a2=20
c=a2+b2=212+202=29
A=π180°arcsin(a/c)=π180°arcsin(21/29)=46.3972=46°2350"
B=π180°arcsin(b/c)=π180°arcsin(20/29)=43.6028=43°3610"
C=90=90



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