Right triangle eq2

Find the lengths of the sides and the angles in the right triangle. Given area S = 210 and perimeter o = 70.

Correct result:

a =  21
b =  20
c =  29
A =  46.3972 °
B =  43.6028 °
C =  90 °

Solution:


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b=2 S/a=2 210/21=20 b=a2=20b=2 \cdot \ S/a=2 \cdot \ 210/21=20 \ \\ b=a_{2}=20
c=a2+b2=212+202=29c=\sqrt{ a^2+b^2 }=\sqrt{ 21^2+20^2 }=29
A=180πarcsin(a/c)=180πarcsin(21/29)=46.3972=462350"
B=180πarcsin(b/c)=180πarcsin(20/29)=43.6028=433610"
C=90=90



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