# Top of the tower

The top of the tower has the shape of a regular hexagonal pyramid. The base edge has a length of 1.2 m, the pyramid height is 1.6 m. How many square meters of sheet metal is needed to cover the top of the tower if 15% extra sheet metal is needed for joints, overlap and waste?

Result

S =  7.074 m2

#### Solution:

$a=1.2 \ \text{m} \ \\ h=1.6 \ \text{m} \ \\ n=6 \ \\ \ \\ h_{2}=\sqrt{ h^2+(a/2)^2 }=\sqrt{ 1.6^2+(1.2/2)^2 } \doteq 1.7088 \ \text{m} \ \\ S_{1}=n \cdot \ \dfrac{ a \cdot \ h_{2} }{ 2 }=6 \cdot \ \dfrac{ 1.2 \cdot \ 1.7088 }{ 2 } \doteq 6.1517 \ \text{m}^2 \ \\ q=15 \%=1 + \dfrac{ 15 }{ 100 }=1.15 \ \\ \ \\ S=q \cdot \ S_{1}=1.15 \cdot \ 6.1517 \doteq 7.0744 \doteq 7.074 \ \text{m}^2$ Our examples were largely sent or created by pupils and students themselves. Therefore, we would be pleased if you could send us any errors you found, spelling mistakes, or rephasing the example. Thank you!

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