# The test

The test contains four questions, and there are five different answers to each of them, of which only one is correct, the others are incorrect. What is the probability that a student who does not know the answer to any question will guess the right answers to all the questions?

Result

p =  0.16 %

#### Solution:

$p=100 \cdot \ (1/5)^{ 4 }=\dfrac{ 4 }{ 25 }=0.16=0.16 \%$ Our examples were largely sent or created by pupils and students themselves. Therefore, we would be pleased if you could send us any errors you found, spelling mistakes, or rephasing the example. Thank you!

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Showing 1 comment: Math student
You make it simple where I can understand thank you so much Tips to related online calculators
Would you like to compute count of combinations?

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