Quadrilateral pyramid

The regular quadrilateral pyramid has a base edge a = 1.56 dm and a height h = 2.05 dm.

Calculate:

a) the deviation angle of the sidewall plane from the base plane
b) deviation angle of the side edge from the plane of the base

Correct result:

A =  69.1688 °
B =  61.7157 °

Solution:

a=1.56 dm h=2.05 dm  tanA=h:(a/2) A=180πarctan(2 h/a)=180πarctan(2 2.05/1.56)=69.1688=69108"
u=2 a=2 1.562.2062 dm  tanB=h:(u/2)  B=180πarctan(2 h/u)=180πarctan(2 2.05/2.2062)=61.7157=614257"



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