Eq2 2

Solve following equation with quadratic members and rational function:

(x2+1)/(x-4) + (x2-1)/(x+3) = 23

Result

x1 =  -2.733
x2 =  5.786
x3 =  8.947

Solution:

$(x^2+1)/(x-4) + (x^2-1)/(x+3) = 23 \ \\ x<>4, x<>-3 \ \\ \ \\ (x^2+1) \cdot \ (x+3) + (x^2-1) \cdot \ (x-4) = 23 \cdot \ (x-4) \cdot \ (x+3) \ \\ \ \\ 2 \ x^3 - 24 \ x^2 + 23 \ x + 283 \ \\ \ \\ x_{ 1 } = -2.7333 = -2.733$
$x_{ 2 } = 5.7863 = 5.786$
$x_{ 3 } = 8.9470 = 8.947$

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