Forces with magnitudes F1 = 42N and F2 = 35N act at a common point and make an angle of 77°12'. How big is their resultant?

Correct answer:

F =  60.3353 N

Step-by-step explanation:

F1=42 N F2=35 N α=77°12=77°+6012°=77.2°=77.2  x0=F1=42 y0=0 x=x0+F2 cosα=x0+F2 cos77.2° =42+35 cos77.2° =42+35 0.221548=49.7542 y=y0+F2 sinα=y0+F2 sin77.2° =0+35 sin77.2° =0+35 0.975149=34.13023 F=x2+y2=49.75422+34.13022=60.3353 N

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