Medians of isosceles triangle

The isosceles triangle has a base ABC |AB| = 16 cm and 10 cm long arm. What are the length of medians?

Correct result:

t1 =  6 cm
t2 =  12.369 cm
t3 =  12.369 cm


t1=10282=6 cmt_1=\sqrt{ 10^{ 2 }-8^{ 2 } }=6 \ \text{cm}

Try calculation via our triangle calculator.

t2=162+522 16 5 cos(arcsin(6/10))=12.369 cmt_2=\sqrt{ 16^{ 2 }+5^{ 2 }-2 \cdot \ 16 \cdot \ 5 \cdot \ \cos(\arcsin(6/10)) }=12.369 \ \text{cm}
t3=t2=12.369 cmt_3 = t_2 = 12.369 \ \text{cm}

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