# Circular pool

The base of the pool is a circle with a radius r = 10 m, excluding a circular segment that determines the chord length 10 meters. The pool depth is h = 2m. How many hectoliters of water can fit into the pool?

Result

x =  6236 hl

#### Solution:

$x=2 \cdot \ 10 \cdot \ (\pi \cdot \ 10^{ 2 } \cdot \ (360-60)/360+10 \cdot \ 5) = 6236 \ \text { hl }$

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