# Surface of the cube

Find the surface of the cube that has volume
1/1m3
2/0.001 m3
3/8000 mm3

Result

S1 =  6 m2
S2 =  0.06 m2
S3 =  2400 mm2

#### Solution:

$V_{1}=1 \ \text{m}^3 \ \\ V=a^3 \ \\ a_{1}=\sqrt{ V_{1}}=\sqrt{ 1 }=1 \ \text{m} \ \\ S_{1}=6 \cdot \ a_{1}^2=6 \cdot \ 1^2=6 \ \text{m}^2$
$V_{2}=0.001 \ \text{m}^3 \ \\ a_{2}=\sqrt{ V_{2}}=\sqrt{ 0.001 }=\dfrac{ 1 }{ 10 }=0.1 \ \text{m} \ \\ S_{2}=6 \cdot \ a_{2}^2=6 \cdot \ 0.1^2=\dfrac{ 3 }{ 50 }=0.06 \ \text{m}^2$
$V_{3}=8000 \ \text{mm}^3 \ \\ \ \\ a_{3}=\sqrt{ V_{3}}=\sqrt{ 8000 }=20 \ \text{mm} \ \\ S_{3}=6 \cdot \ a_{3}^2=6 \cdot \ 20^2=2400 \ \text{mm}^2$ Our examples were largely sent or created by pupils and students themselves. Therefore, we would be pleased if you could send us any errors you found, spelling mistakes, or rephasing the example. Thank you!

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