Coordinates of a centroind

Let’s A = [3, 2, 0], B = [1, -2, 4] and C = [1, 1, 1] be 3 points in space. Calculate the coordinates of the centroid of △ABC (the intersection of the medians).

Correct result:

x =  1.6667
y =  0.3333
z =  1.6667

Solution:

$y=\frac{{y}_{0}+{y}_{1}+{y}_{2}}{3}=\frac{2+\left(-2\right)+1}{3}=\frac{1}{3}=0.3333$
$z=\frac{{z}_{0}+{z}_{1}+{z}_{2}}{3}=\frac{0+4+1}{3}=\frac{5}{3}=1.6667$

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